WebThe answer is 375. Get the stepwise instructions to find GCF of 1125 and 4125 using prime factorization method. Answers. Solutions by everydaycalculation.com. Answers.everydaycalculation.com » GCF of two numbers. What is the GCF of 1125 and 4125? ... Find hcf of: 2250 & 8250 375 & 1375 225 & 825 2250 & 4125 1125 & 8250 … WebThe HCF of (a m - 1) and (a n - 1) is given by (a HCF of m, n - 1) Thus for this question the answer is (3 5 - 1) Since, 5 is the HCF of 35 and 125. Join The Discussion. Comment * Comments ( 1) Shailajakshi Earamala : 6 years ago . In this question there s a mistake. It should be 30 not 35. If I'm correct or wrong tell me. Sorry for ths comment.
HCF Calculator Find the Highest Common Factor of given
WebClick here👆to get an answer to your question ️ The L.C.M. and H.C.F. of two numbers are 4125 and 25 respectively. One number is 375. Find by how much is the second number less than the first? Solve Study Textbooks Guides. Join / Login. ... The HCF of two numbers 3 0 6, 6 5 7 is 9. Find the LCM of these two numbers. Medium. View solution > WebApr 6, 2024 · Step 1: Since 2475 > 2310, we apply the division lemma to 2475 and 2310, to get 2475 = 2310 x 1 + 165. Step 2: Since the reminder 2310 ≠ 0, we apply division lemma to 165 and 2310, to get 2310 = 165 x 14 + 0. The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 165, the HCF of 2475 and 2310 is 165 is the nintendo switch worth it in 2022
1375/825 simplified, Reduce 1375/825 to its simplest form
WebThe Greatest Common Factor (GCF) for 125 and 45, notation CGF (125,45), is 5. Explanation: The factors of 125 are 1,5,25,125; The factors of 45 are 1,3,5,9,15,45. So, … WebThe highest common factor (HCF) of any set of numbers is the largest possible number which divides the given numbers exactly without any remainder. Given that, LCM (2472, 1284, and n) is 2 3 × 3 2 × 5 × 103 × 107. Let us express the numbers 2472, and 1284 as a product of prime numbers. WebSince the divisor at this stage is 625, the HCF of 625 and 3125 is 625. Notice that 625 = HCF (3125,625) . We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma. Step 1: Since 15625 > 625, we apply the division lemma to 15625 and 625, to get. 15625 = 625 x 25 + 0. The remainder has now become zero, so ... i heart c4