WebA sled of mass 70 kg starts from rest and slides down a 10 incline 80 m long. ... has speed 1.40 m/s at the crest of a slope 2.60 m high and 12.4 m long. ... A 75.0-kg person climbs stairs, gaining 2.50 meters in height. Find the work done to accomplish this task. Web13 nov. 2024 · Explanation: Given data: Mass of person = 60 Kg Mass of sled = 15 kg Applied force = 300 N Acceleration = ? Solution: Formula: F = ma F = force m = mass a = acceleration now we will put the values in formula. 300 N = (60 Kg+ 15 kg) × a 300 N = 75 Kg × a a = 300 N/ 75 Kg N = kgm/s² a = 4 ms⁻² Advertisement Advertisement

If a 60 kg person on a 15 kg sled is pushed with a force of 300 N, …

Web8. If a 60 kg person on a 15 kg sled is pushed with a force of 300 N, what will be person’s acceleration? 9. A force of 20 N acts upon a 5 kg block. Calculate the acceleration of the object. 10. An object of mass 300 kg is observed to accelerate at the rate of 4 m/s2. Calculate the force required to produce this acceleration. 11. WebIf a 60 kg person on a 15 kg sled is pushed with a force of 300 N, what will be the person's acceleration? Equation? a=F/m What am I looking for? Acceleration What do I know? … tic toc gypsy xo

Force Mass Acceleration Problems.docx - Practice Problem...

Web8. If a 60 kg person on a 15 kg sled is pushed with a force of 300 N, what will be person’s acceleration? F=ma 300N=(60+15)(a) a=4 m/s2. 9. A force of 20 N acts upon a 5 kg block. Calculate the acceleration of the object. F=ma 20N=5(a) a=4 m/s2. 10. An object of mass 300 kg is observed to accelerate at the rate of 4 WebExpert Answer 8) The mass of the person (m) = 60 kg The mass of the sled (m') = 15 kg The total mass = M = (m + m') = (60+15) = 75 kg The applied force (F) = 300 N We know, F = Ma [Where, a = Acceleration ] 300 = 75 × a … WebIf a 60 kg person on a 15 kg sled is pushed with a force of 300 N, what will be the person's acceleration? 300 N ÷ 75 kg = 4 m/sec2. A force of 250 N is applied to an object that … the lumineers cape town