WebSolution We have, Median=14.4 Clearly, it lies in the class interval 12-18.So, 12-18 is the median class. ∴ l=12, h=6, f=5 anf F=4+x and N 2 = 10 So, M edian= l+ N 2−F f ×h => 14.4= 12+ 10−(4+x) 5 ×6 => 2.4× 5 6= 10−(4+x) 2 =6−x ; x=4 and also, 10+x+y=10 ⇒10+4+y=20 ⇒y=6 answer= x= 4 and y= 6 Suggest Corrections 58 Similar questions Q. Web6 If the mean of the following data is 14.7, find the values of p and q. Class 0-6 6-12 12-18 18-24 24 - 30 30- 36 36-42 Total Frequency 10p147 941 40 Solution Verified by Toppr …
How To Calculate The Mean Of Variables In R
Web9 nov. 2024 · The following steps can be used to compute the mean of the given data distribution: Step 1: Create a table having four columns as computed below, Column 1- … Web6 If the mean of the following data is 14.7, find the values of p and q. Class 0-6 6-12 12-18 18-24 24 - 30 30- 36 36-42 Total Frequency 10p147 941 40 Solution Verified by Toppr Solve any question of Statistics with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions Find HCF of 54,81 and 99. Easy View solution > eggplant with tomato sauce recipe
Solved S 1.7 Mean and Standard Deviations 4 For each of the
WebQ. Find the mean of the following data using assumed mean method: Q. Find the mean deviation about the mean of the following data: 15, 17, 10, 13, 7, 18, 9, 6, 14, 11. Q. … WebIOP reduction ≥20% without medication was achieved in 89%, 90%, and 92% of one-, two-, and three-stent eyes, respectively, at Month 12; and in 61%, 91%, and 91% of eyes, respectively, at Month 42. The need for additional medication remained consistent at Months 12 and 42 in multi-stent eyes (four two-stent eyes and three three-stent eyes at ... WebS 1.7 Mean and Standard Deviations 4 For each of the following sets of data, calculate (a) the overall mean and (b) the overall standard deviation 2 45.6 58.9 35.4 28.9 44.8 75.3 … foldable wireless keyboard singapore